Team:Calgary/Modelling/Method
From 2009.igem.org
(Difference between revisions)
Line 129: | Line 129: | ||
<tr> | <tr> | ||
<td>Species</td> | <td>Species</td> | ||
- | <td>Initial Value</td> | + | <td> Initial Value </td> |
<td>Rationale</td> | <td>Rationale</td> | ||
</tr> | </tr> | ||
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<td>AI-2</td> | <td>AI-2</td> | ||
<td>0</td> | <td>0</td> | ||
- | <td>Initially the amount of AI-2 is constant. After an equilibruim is established variable amounts of AI-2 | + | <td>Initially the amount of AI-2 is constant at 0. After an equilibruim is established variable amounts of AI-2 are added at different simulations.</td> |
</tr> | </tr> | ||
<tr> | <tr> | ||
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<td>AI-2:LuxPQ</td> | <td>AI-2:LuxPQ</td> | ||
<td>0</td> | <td>0</td> | ||
- | <td>This value is kept | + | <td>This value is kept at time = 0 because the initial concentration of AI-2 is 0. </td> |
</tr> | </tr> | ||
<tr> | <tr> | ||
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<td>LuxO:p</td> | <td>LuxO:p</td> | ||
<td>2</td> | <td>2</td> | ||
- | <td>Equal amounts of LuxO:p and LuxU:p was considered in the model because LuxU:p phosphorylates LuxO . The phosphorylation reaction is considered to be a fast reaction therefore there are equal amounts of the two | + | <td>Equal amounts of LuxO:p and LuxU:p was considered in the model because LuxU:p phosphorylates LuxO . The phosphorylation reaction is considered to be a fast reaction therefore there are equal amounts of the two proteins present.</td> |
</tr> | </tr> | ||
<tr> | <tr> | ||
- | <td>LuxO | + | <td>LuxO</td> |
- | <td> | + | <td>1000</td> |
- | <td> | + | <td>There are equal amounts of LuxO and LuxU present since they are encoded within the same operon in the cell.</td> |
</tr> | </tr> | ||
<tr> | <tr> | ||
<td>p</td> | <td>p</td> | ||
- | <td> | + | <td>10.0658</td> |
- | <td> | + | <td>We assume that there is enough p is the environment that it doesn’t become a limiting factor. For that reason we assign p as a constant value in simbiology. (It doesn’t really matter that the initial amount is presented as a comparatively small number in this case. ) </td> |
</tr> | </tr> | ||
<tr> | <tr> | ||
<td>sigma54</td> | <td>sigma54</td> | ||
- | <td> | + | <td>0.14183</td> |
- | <td> | + | <td>This amount is kept at a constant value to ensure that this value does not become a limiting factor.</td> |
</tr> | </tr> | ||
<tr> | <tr> | ||
<td>sigma54:LuxO:p:Pqrr4</td> | <td>sigma54:LuxO:p:Pqrr4</td> | ||
- | <td> | + | <td>0.63</td> |
- | <td> | + | <td> There is only 1 copy of Pqrr4 present in each cell . since in the reaction equations Pqrr4 is shared between 2 other equations we decided to break the concentration of Pqrr4 between 3 species: sigma54:LuxO:p:Pqrr4 , Pqrr4 , sigma54:Pqrr4 . The initial values of the three species add up to one. The fractions of the Pqrr4 combination species are weighted differently . Since the Pqrr4 promotor stays on most of the time we decided the sigma54:LuxO:p:Pqrr4 complex should recieve the most weight. Pqrr4 is assumed to stay unbound from any complex for the least amount of time therefore Pqrr4 initial amount is the smallest. </td> |
</tr> | </tr> | ||
<tr> | <tr> | ||
<td>Sigma54:Pqrr4</td> | <td>Sigma54:Pqrr4</td> | ||
- | <td> | + | <td>0.345</td> |
<td> </td> | <td> </td> | ||
</tr> | </tr> | ||
<tr> | <tr> | ||
<td>Pqrr4</td> | <td>Pqrr4</td> | ||
- | <td> | + | <td>0.025</td> |
<td> </td> | <td> </td> | ||
</tr> | </tr> |
Revision as of 18:37, 20 October 2009
UNIVERSITY OF CALGARY
DIFFERENTIAL EQUATIONS MODELLING METHODS
The simbiology interface from Matlab was used to simulate the differential equations model. Chemical Kinetic equations were used to build the model for simulation.
[A] is the amount of reactant A present. The simulations were run for 50000 seconds . It was considered to be enough time for the system to reach equilibrium after disturbance. The Sundials Solver (how do they work ?)was used to run these simulations because for this model it was considered to produce optimal results. (how do simulations work?) The Reactions
The system was represented by the following reactions. The reactions with double headed arrows have two rate constants(forward/ reverse rate constant). All reactions were assumed to be elementary reactions.
Parameter Rationale
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