Team:IBB Pune/Modeling

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Modelling

The aim of the modelling aspect of our project is to develop simulations that would enable us to predict the behavior of the export tag with the Snowdrift Game as the backdrop. </p>

For example, in our system, knowing of the -----------is crucial and if one attempted to find the optimal level of ======in the lab, the cost of experiment would rise and it would take days and months to figure out. With an accurate model, however, we would be able to predict the optimal level --------------within a matter of seconds, which would result in a cheaper and much efficient experiment. Through these models, we seek to answer different questions, as noted below: 1 2 3

Project 1- A Model Of The Snowdrift Game

<p>This is a Model of the Snowdrift game. This model assumes use of two different strains as co-operators and defectors.

Co-operators constitutively secrete/produce b-gal. Defectors cannot secrete/produce B-gal.

This model is for a Single iteration of the experiment. i.e. the culture is initiated in shaker flask and allowed to grow.

In order to find ESS or stable equilibria, we will have to repeatedly subculture the cells under similar conditions, by replacing the medium or supplying fresh medium. In such a setup, the input for the next cycle of experiments will be the output of the previous cycle of experiments.

Assumptions

At time t=0;

There are 'k' co-operators and 'N-k' defectors

Medium contains 'L' mg/ml of lactose, glucose conc. (g) = 0

Culture is well mixed.

Extracellular Enzyme conc (Ec) = 0 units/ml

Artificial assumptions

Glucose is consumed by all cells. Galactose is also consumed at the same rate Gc mg/cell/min/ml. The metabolic benefit due to glucose and galactose is same.So effectively each lactose molecule gives rise to 2 glucose molecules

There is no intracellular lactose metabolism (only extracellular).

There is no lag in enzyme production and secretion.

Rate of degradation of enzyme is zero

Model

In this Model,

1. Each co-operator secretes 'B' units of enzyme/ min and pays cost of 'c' / min

These molecules diffuse freely through the medium

They convert Lactose to Glucose + Galactose given by

Rate of conversion of lactose to glucose is given by (k2)*(Ec)*(L) g mg/ml/min

Absorbed glucose confers growth rate advantage of r Advantage conferred by Glucose r= (R)*(g)*(Gc)

After each min, the population of co-operators and defectors is updated depending upon the growth rates.

D(t) = D(t-1)+r*D(t-1) Defector population

k(t) = k(t-1) + (r-c)*k(t-1) Co-operator population

Equations

C=C0+C*((R*G0*Gc)-cost) D=D+D*R*Gc*G0 L=L-L*Ec*k2 G=G+((2*L*Ec*k2)-(N*Gc)