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Team:Uppsala-Sweden/Modelling
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Where ''ks'' is the rate of substrate formation (flux of the glycolysis), ''kcat'' is the maximum number of enzymatic reactions catalyzed per second for the intoduced pathway, ''kt'' is the rate constant for the loss of substrate to other pathways, in our case primarily to the Krebbs cycle, ''Km'' is the substrate concentration at half the maximum reaction rate (''Vmax'') and ''s'' is the substrate concentration. | Where ''ks'' is the rate of substrate formation (flux of the glycolysis), ''kcat'' is the maximum number of enzymatic reactions catalyzed per second for the intoduced pathway, ''kt'' is the rate constant for the loss of substrate to other pathways, in our case primarily to the Krebbs cycle, ''Km'' is the substrate concentration at half the maximum reaction rate (''Vmax'') and ''s'' is the substrate concentration. | ||
| - | Having the ''Km'' and ''Kcat'' values gives ''e0'' from the level of product formation. | + | Having the ''Km'' and ''Kcat'' values (obtained in literature) gives ''e0'' from the level of product formation, rewritten equation (c). |
(d) [[Image:ek_3.png]] | (d) [[Image:ek_3.png]] | ||
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| - | 4. Assuming ''ks'' to be constant within the interval and assuming steady-state (''d''s/''d''t = 0) and rearranging to a 2:nd degree equation. | + | 4. Assuming ''ks'' to be constant within the interval and assuming steady-state (''d''s/''d''t = 0) and rearranging to a 2:nd degree equation which is easily solved numerically. |
(f) [[Image:ek_5.png]] | (f) [[Image:ek_5.png]] | ||
| - | ''S'' is a function of ''f(x,y)'' where x is proportional to ''e0'' and y is proportional to ''kt'' through the fitting constants A and B which are determined by measuring the substrate (pyruvate) concentration at different levels of enzyme concentration and inhibition of the PDC. In other words this correlates with the activity | + | ''S'' is a function of ''f(x,y)'' where x is proportional to ''e0'' and y is proportional to ''kt'' through the fitting constants A and B which are determined by measuring the substrate (pyruvate) concentration at different levels of enzyme concentration and inhibition of the PDC. In other words this correlates with the activity of the promoters for the ethanol construct and the PDC inhibiting construct determining the two main outflux paths for pyruvate respectively. These are then the two factors we can change in the system by using two different inducible promoters. |
The solution to the equation gives a negative square root as the second answer which can be disregarded as both ''A'' and ''B'' are always positive and negative substrate levels are not physically acceptable. | The solution to the equation gives a negative square root as the second answer which can be disregarded as both ''A'' and ''B'' are always positive and negative substrate levels are not physically acceptable. | ||
Revision as of 01:13, 22 October 2009
Modelling of Ethanol Production
In order to be able to model the system under the restraints mentioned above we have made some basic assumptions:
1. Co-evolution of the of the ethanol producing pathway, this making Km and kcat highly similar for the pdc and Adh2.
This assumption is quite logic as these enzymes comes from the same metabolic pathway in the native organism. In practice this assumption makes it possible for us to model the system as a single step reaction from pyruvate to ethanol, greatly increasing the ease of simulation.
2. Assuming quasi steady state (Michaelis Menten Kinetics), that is constant total enzyme and substrate concentration.
This is reasonable during log-phase when cell volumes are constant and before ethanol starts to inhibit growth.
Assumption #2 leads to equation (a)
(a)
Where e is the amount of free enzyme and es is the amount of enzyme bound to substrate and e0 being the total concentration of enzyme.
Assumption #2 also gives equation (b) being simply the expression for the change of substrate concentrations over time, that is influx minus outflux. If we assume constant substrate concentration as in #2 the change in product concentration is given by influx substrate ks minus outflux through other paths than ethanol kt*s. Rewritten this yields equation (c).
(b & c) 
Where ks is the rate of substrate formation (flux of the glycolysis), kcat is the maximum number of enzymatic reactions catalyzed per second for the intoduced pathway, kt is the rate constant for the loss of substrate to other pathways, in our case primarily to the Krebbs cycle, Km is the substrate concentration at half the maximum reaction rate (Vmax) and s is the substrate concentration.
Having the Km and Kcat values (obtained in literature) gives e0 from the level of product formation, rewritten equation (c).
(d) 
3. Having e0 and letting kt go towards zero gives ks. kt can be assumed to approach zero provided that the Krebbs cycle is the main native consumer of pyruvate and that the inhibition of the PDC is successful. Gives a rearranged equation (b).
(e) 
4. Assuming ks to be constant within the interval and assuming steady-state (ds/dt = 0) and rearranging to a 2:nd degree equation which is easily solved numerically.
(f) 
S is a function of f(x,y) where x is proportional to e0 and y is proportional to kt through the fitting constants A and B which are determined by measuring the substrate (pyruvate) concentration at different levels of enzyme concentration and inhibition of the PDC. In other words this correlates with the activity of the promoters for the ethanol construct and the PDC inhibiting construct determining the two main outflux paths for pyruvate respectively. These are then the two factors we can change in the system by using two different inducible promoters.
The solution to the equation gives a negative square root as the second answer which can be disregarded as both A and B are always positive and negative substrate levels are not physically acceptable.
(g) 
Measure for different x and y (activity of the two promoters) and fit the function to data through A and B.
Integrating (c) gives the final expression for product levels dependent only on the activity of the promoters, given our assumptions are reasonably correct. The assumption that we don't have any product (ethanol) at t=0 gives D=0
(h) 
Through this equation (h) we can at various levels of substrate determined by (g) optimize the promoter activities for the ethanol construct and the PDC inhibiting construct so that maximum product yield is reached.
