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Team:IBB Pune/Modeling
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1. Each co-operator secretes ''''B' units of enzyme/ min and pays cost of 'c' / min''' | 1. Each co-operator secretes ''''B' units of enzyme/ min and pays cost of 'c' / min''' | ||
| - | These molecules diffuse freely through the medium | + | 2. These molecules diffuse freely through the medium |
| - | They convert Lactose to Glucose + Galactose given by | + | 3. They convert Lactose to Glucose + Galactose given by |
| - | Rate of conversion of lactose to glucose is given by (k2)*(Ec)*(L) | + | 4. Rate of conversion of lactose to glucose is given by (k2)*(Ec)*(L) |
g mg/ml/min | g mg/ml/min | ||
| - | Absorbed glucose confers growth rate advantage of '''r''' | + | 5. Absorbed glucose confers growth rate advantage of '''r''' |
Advantage conferred by Glucose r= (R)*(g)*(Gc) | Advantage conferred by Glucose r= (R)*(g)*(Gc) | ||
Revision as of 11:29, 21 October 2009
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Modelling
The aim of the modelling aspect of our project is to develop simulations that would enable us to predict the behavior of the export tag with the Snowdrift Game as the backdrop.
Project 1- A Model Of The Snowdrift Game
Model
This is a Model of the Snowdrift game. This model assumes use of two different strains as co-operators and defectors.
Co-operators constitutively secrete/produce b-gal. Defectors cannot secrete/produce B-gal.
This model is for a Single iteration of the experiment i.e. the culture is initiated in shaker flask and allowed to grow. In order to find ESS or stable equilibria, we will have to repeatedly subculture the cells under similar conditions, by replacing the medium or supplying fresh medium. In such a setup, the input for the next cycle of experiments will be the output of the previous cycle of experiments.
Contents
Assumptions
At time t=0;
- There are 'k' co-operators and 'N-k' defectors
- Medium contains 'L' mg/ml of lactose, glucose conc. (g) = 0
- Culture is well mixed.
- Extracellular Enzyme conc (Ec) = 0 units/ml
Artificial assumptions
Glucose is consumed by all cells. Galactose is also consumed at the same rate Gc mg/cell/min/ml.
- The metabolic benefit due to glucose and galactose is same.So effectively each lactose molecule gives rise to 2 glucose molecules
There is no intracellular lactose metabolism (only extracellular).
There is no lag in enzyme production and secretion.
Rate of degradation of enzyme is zero
Model
In this Model,
1. Each co-operator secretes 'B' units of enzyme/ min and pays cost of 'c' / min
2. These molecules diffuse freely through the medium
3. They convert Lactose to Glucose + Galactose given by
4. Rate of conversion of lactose to glucose is given by (k2)*(Ec)*(L) g mg/ml/min
5. Absorbed glucose confers growth rate advantage of r Advantage conferred by Glucose r= (R)*(g)*(Gc)
After each min, the population of co-operators and defectors is updated depending upon the growth rates.
D(t) = D(t-1)+r*D(t-1) Defector population
k(t) = k(t-1) + (r-c)*k(t-1) Co-operator population
Equations
the Lactose that remains at time 't' L=L-L*Ec*k2
The net Glucose present in the medium: G=G+((2*L*Ec*k2)-(N*Gc)
Results
File:Pidt smart.JPGSnapshot of pIDT Smart-Kan vector containing YcdB gene
.JPG)
